If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4^x+2^1+2x=40
We move all terms to the left:
4^x+2^1+2x-(40)=0
determiningTheFunctionDomain 4^x+2x-40+2^1=0
We add all the numbers together, and all the variables
2x+4^x-38=0
We move all terms containing x to the left, all other terms to the right
2x+4^x=38
| 5+s=40 | | 5x+15=60+2x | | 2.89x^2=x^2+9 | | n^2-8n=-10 | | (2+x)^2=64 | | 5m-3(m-1/2)=(3/2+2m) | | 2(y-3)=1.2-y. | | |12-2x|=-6 | | 10/y=3/17 | | 384=3x*2x*x | | (6w+2)(5W^2-4w-7)=0 | | 2(x-1)=7(x+1) | | 3/4w·=6 | | 4+3(x-5)=2(x+5) | | 2x-8÷3=4 | | 3(5x^2-2x^2-50)-23(7x^2+98x-2)=45 | | 3(z+5)=2z+5 | | 30.5+12x=78.5 | | w-1.16=3.6 | | 4=x= | | 12w^2+5W-7=0 | | y+3.6=9.36 | | v+6.6=9.41 | | 27-13t+32-2t+10t= | | 96+y=180 | | 7a=78 | | (x+2)/3=2/3 | | X^3-5x-7=0 | | 180n-360=156n | | 125x=75 | | 2048=2x*x | | 8.15x+42.55=85.1 |